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Question
primary 5 | Maths
| Whole Numbers
One Answer Below
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Date Posted: 2 years ago
Views: 239
T = D+E+F = 3×52 = 156
F:D:E : T
= u+9+6 : u+9 : u : 3u+24
3u+24 = 156
u = (156-24)÷3 = 44
F
= u+9+6
= 44+9+6
= 59 (Ans)
F:D:E : T
= u+9+6 : u+9 : u : 3u+24
3u+24 = 156
u = (156-24)÷3 = 44
F
= u+9+6
= 44+9+6
= 59 (Ans)
See 1 Answer
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Date Posted:
2 years ago
Thanks
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