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secondary 4 | E Maths
2 Answers Below
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pls help! thank you
2x² + x = 8 ①
2x² = 8 - x
Multiply both sides by x,
2x³ = 8x - x² ②
Then,
2x³ + 17x² + 123
= 8x - x² + 17x² + 123 (sub in ②)
= 16x² + 8x + 123
= 8(2x² + x) + 123
= 8(8) + 123 (sub in ①)
= 64 + 123
= 187
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Working has been given in the question's comments section.
So strictly speaking,
When we are dividing 2x³ + 17x² + 123 by 2x² + x - 8 , we are dividing by 0. And division by 0 is undefined.
If I were the teacher I would mark this correct, but I'm not sure what the perspective of the student's marker/teacher will be.
Eg. Something along the lines of 187 × 0 = 0, but we can only say that 0/187 = 0 and not 187/0 = 0 or 0/0 = 187.
That's why I decided not to go with this approach, but the other one instead.
2x² + x - 8 = 0
2x² + x = 8 ①
2x² = 8 - x
Multiply both sides by x,
2x³ = 8x - x² ②
Then,
2x³ + 17x² + 123
= 8x - x² + 17x² + 123 (sub in ②)
= 16x² + 8x + 123
= 8(2x² + x) + 123
= 8(8) + 123 (sub in ①)
= 64 + 123
= 187
Eg. Divide 2x³ + 17x² + 123 by 2x² + x - 8 , where neither is equated to anything.
I also said if I were the marker, I would mark your working as right so of course I'm not against it.
Of course we all know long division is commonly used here.
So chill a bit yea.