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secondary 4 | A Maths
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need help with this qn, please explain too
Perimeter of bigger △ is 3 sides of it.
Since you're given 1 : 2,
6 small sides : 3 big sides = 1 : 2
6 small sides × 2 = 3 big sides
12 small sides = 3 big sides
1 big side = 4 small sides
Ratio of 1 small △ side : 1 big △ side
= 1 : 4
Both are equilateral △ so they are similar.
Area ratio of 1 small △ to 1 big △
= 1² : 4²
= 1 : 16
Area of 6 small △ (which is area of one hexagon) : area of big△
= 6 : 16
= 3 : 8
Ratio of side of small △: side of big △
= (1÷6) : (2÷3)
= 1/6 : ⅔
= 1 : 4
(Multiply both by 6)
Ratio of area of 1 small △ : 1 big △
= 1² : 4²
= 1 : 16
Ratio of hexagon area : △
= (6×1) : 16
= 6 : 16
= 3 : 8
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