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secondary 4 | A Maths
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Solve for t in terms of w. This is what I have solved so far but there is still t on the left side. Please help thanks.
Date Posted: 3 years ago
Views: 236
Shouldn't factor t out. Wait ah
From this step :
5w² = t² - 2wt - 3w²
t² - 2wt - 3w² - 5w² = 0
t² - 2wt - 8w² = 0
Factorise this.
(t + 2w)(t - 4w) = 0
t + 2w = 0 or t - 4w = 0
t = -2w (rejected as this would make the argument in the logarithms a negative value. The logarithm would then be undefined)
or t = 4w
5w² = t² - 2wt - 3w²
t² - 2wt - 3w² - 5w² = 0
t² - 2wt - 8w² = 0
Factorise this.
(t + 2w)(t - 4w) = 0
t + 2w = 0 or t - 4w = 0
t = -2w (rejected as this would make the argument in the logarithms a negative value. The logarithm would then be undefined)
or t = 4w
Note that w has to be a positive value for the logarithm to be defined in the first place.
In addition, the base of the logarithm cannot be 1.
In addition, the base of the logarithm cannot be 1.
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