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secondary 2 | Maths
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I have to first work out the gradient of the line using the given points.
Date Posted: 2 years ago
Views: 407
You don't really have to do that.
The gradient found using any 2 points will be the same as another set of 2 points.
Formula for gradient : (y2 - y1)/(x2 - x1)
So, we can have the following sets :
(-1,-1) & (k,23)
(k,23) and (3,15)
The gradients calculated are equal.
(23 - (-1))/(k - (-1)) = (15 - 23)/(3 - k)
24 / (k + 1) = -8/(3 - k)
Cross multiply,
24(3 - k) = -8(k + 1)
72 - 24k = -8k - 8
72 + 8 = -8k + 24k
80 = 16k
k = 80/16 = 5
The gradient found using any 2 points will be the same as another set of 2 points.
Formula for gradient : (y2 - y1)/(x2 - x1)
So, we can have the following sets :
(-1,-1) & (k,23)
(k,23) and (3,15)
The gradients calculated are equal.
(23 - (-1))/(k - (-1)) = (15 - 23)/(3 - k)
24 / (k + 1) = -8/(3 - k)
Cross multiply,
24(3 - k) = -8(k + 1)
72 - 24k = -8k - 8
72 + 8 = -8k + 24k
80 = 16k
k = 80/16 = 5
thank you so much you've helped me a lot i understand it now:) x
Welcome
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hope this helpsss
Date Posted:
2 years ago
Thank You So Much! I appreciate it:)
thank you so much i truly appreciate it!! x
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