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for quadratic equations of the form y=ax^2 + bx + c
use the formula x = -b/2a to find the x coordinate of the turning point.
use the formula x = -b/2a to find the x coordinate of the turning point.
Date Posted:
3 years ago
Thank you so much for explanation
h is 126 +p and how t is 5 sec
alternatively you can use the method of how MAXIMUM point is (-b/2a).
in this equation,
h = -5t^2 + 50t + p + 1
so a = -5, b = 50, c = p+1
(look at the coefficients. what comes before "t^2" will be your a, what comes before "t" will be your b and what is left will be your c. *take note of your positive & negative signs!)
so maximum point would be
-50 / 2(-5) = -50 / -10 = 5
hope this helps!