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primary 6 | Maths
| Measurement
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Pls help
Date Posted: 3 years ago
Views: 385
Since all three digits are the same, there are only 10 possibilities :
000,111,222,333,444,555,666,777,888,999
No need to consider 000 because it is not even a number and 0 has an infinite number of factors except 0 itself.
0 ÷ 1 = 0
0 ÷ 2 = 0
0 ÷ 3 = 0,
and so on.
Division by 0 is undefined and 0/0 is indeterminate
Consider 111 first. The other higher numbers are all multiples of 111.
111 = 111 × 1 = 37 × 3
There are 4 factors. (1,3,37,111) 37 is a prime number so it can only be divided by itself or 1.
So A is 1.
We don't need to consider the rest since they will have more factors than 111, as they are already multiples of 111.
Eg. 444 = 444 × 1 = 222 × 2 = 111 × 4 = 37 × 3 × 4 = 37 × 12 = 37 × 4 × 3 = 148 × 3
000,111,222,333,444,555,666,777,888,999
No need to consider 000 because it is not even a number and 0 has an infinite number of factors except 0 itself.
0 ÷ 1 = 0
0 ÷ 2 = 0
0 ÷ 3 = 0,
and so on.
Division by 0 is undefined and 0/0 is indeterminate
Consider 111 first. The other higher numbers are all multiples of 111.
111 = 111 × 1 = 37 × 3
There are 4 factors. (1,3,37,111) 37 is a prime number so it can only be divided by itself or 1.
So A is 1.
We don't need to consider the rest since they will have more factors than 111, as they are already multiples of 111.
Eg. 444 = 444 × 1 = 222 × 2 = 111 × 4 = 37 × 3 × 4 = 37 × 12 = 37 × 4 × 3 = 148 × 3
See 1 Answer
There are only 9 possible answers. 111, 222... to 999.
111 only has 4 factors, being 1 & 111, 3 & 37. Other numbers are all a multiple of 111, hence they will have more factors and is invalid.
Hence answer is 111.
111 only has 4 factors, being 1 & 111, 3 & 37. Other numbers are all a multiple of 111, hence they will have more factors and is invalid.
Hence answer is 111.
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