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secondary 4 | E Maths
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Jonathan
Jonathan

secondary 4 chevron_right E Maths chevron_right Singapore

Hello, Manytutors if you see this there is an issue with uploading questions online for all subjects, hence have to ask it under "E math" (as app online has e and a math selection).

Can I know how to get D?

Date Posted: 3 years ago
Views: 194
J
J
3 years ago
In potassium manganate (VII) (KMnO4), the Mn⁷⁺ ions are reduced to Mn²⁺ ions


So, solution M must have had a reducing agent in to reduce those Mn⁷⁺ ions

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Arnold K H Tan
Arnold K H Tan's answer
2165 answers (A Helpful Person)
1st
Fundamental fact from topic 6.2 redox. KMnO4 is used srd to test for reducing agents.


Topic 1.3. Used to test for SO2 gas