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secondary 3 | A Maths
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help pls
Date Posted: 3 years ago
Views: 241
(sec θ - tan θ)²
= (1/cos θ - sin θ / cos θ)²
= ((1 - sin θ)/cos θ)²
= (1 - sin θ)² / cos² θ
= (1 - sin θ)² / (1 - sin² θ)
= (1 - sin θ)² / [(1 - sin θ)(1 + sin θ)]
= (1 - sin θ) / (1 + sin θ)
= (1/cos θ - sin θ / cos θ)²
= ((1 - sin θ)/cos θ)²
= (1 - sin θ)² / cos² θ
= (1 - sin θ)² / (1 - sin² θ)
= (1 - sin θ)² / [(1 - sin θ)(1 + sin θ)]
= (1 - sin θ) / (1 + sin θ)
can help with the other one as well?
The one below? Hold on.
yep
cot² x - cos² x
= cos² x / sin² x - cos² x
= cos² x / sin² x - (sin² x cos² x) / sin² x
= (cos² x - sin² x cos² x) / sin² x
= (cos² x)(1 - sin² x) / sin² x
= (cos² x)(cos² x) / sin² x
= cot² x cos² x
= cos² x / sin² x - cos² x
= cos² x / sin² x - (sin² x cos² x) / sin² x
= (cos² x - sin² x cos² x) / sin² x
= (cos² x)(1 - sin² x) / sin² x
= (cos² x)(cos² x) / sin² x
= cot² x cos² x
thanks a lot
Edited for clarity.
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