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secondary 4 | Physics
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Date Posted: 2 years ago
Views: 264
The longer the wire, the more resistance the wire has
(imagine trying to crawl through a pipe of twice the distance)
The bigger the diameter (and therefore the bigger the area), the smaller the resistance
(imagine the previously difficult-to-crawl-through hole is now upsized)
R = pL/A
R = pL/(pi x d x d)
R = (p/pi) times (L / d^2)
p/pi remains unchanged for all wires, so we just look at the values of L / d^2. The smallest of these yields the smallest resistance.
(imagine trying to crawl through a pipe of twice the distance)
The bigger the diameter (and therefore the bigger the area), the smaller the resistance
(imagine the previously difficult-to-crawl-through hole is now upsized)
R = pL/A
R = pL/(pi x d x d)
R = (p/pi) times (L / d^2)
p/pi remains unchanged for all wires, so we just look at the values of L / d^2. The smallest of these yields the smallest resistance.
Short and thick wires are usually those having the least resistances, while the tall and thin wires are usually those having the greatest resistances.
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Hope this helps
Date Posted:
2 years ago
and also take note of the different units for length and diameter, ensure that they have the same units before you sub into eqn
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