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Let markers in box B be x.
Box B X
Box A 1.25X
Box C 0.75X
Total of 420 marker taken from B and C combined which means:
0.3(X)+0.3(0.75X)=420
0.3x+0.225x =420
X=800
Total markers taken from box A,B,C:
0.3(800)+0.3(1.25*800)+(0.3*0.75)*800=720
Markers in each packet:
720/45=16 (answer)
Box B X
Box A 1.25X
Box C 0.75X
Total of 420 marker taken from B and C combined which means:
0.3(X)+0.3(0.75X)=420
0.3x+0.225x =420
X=800
Total markers taken from box A,B,C:
0.3(800)+0.3(1.25*800)+(0.3*0.75)*800=720
Markers in each packet:
720/45=16 (answer)