Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
primary 6 | Maths
| Data Analysis
3 Answers Below
Anyone can contribute an answer, even non-tutors.
Help needed. Thank you
Date Posted: 3 years ago
Views: 281
See 3 Answers
Thank you so much
Thank you so much
Thank you
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
This works?
Date Posted:
3 years ago
Yes, thank you so much
Farid can paint a house in 6 days.
In 1 day, he paints 1/6 of a house.
Gan can paint a house in 9 days.
In 1 day, he paints 1/9 of a house.
Henry can paint a house in 10 days.
In 1 day, he paints 1/10 of a house.
If they work together, fraction of a house they can paint in 1 day = 1/6 + 1/9 + 1/10
= 15/90 + 10/90 + 9/90
= 34/90
= 17/45
(Lowest common multiple is 90, so change all the denominators to 90 first. Then simplify the resulting fraction)
Please note that the assumption here is that they don't take any breaks and there are no overlaps in their painting areas)
Number of days needed = 1 ÷ 17/45
= 45/17
= 2 11/17
In 1 day, he paints 1/6 of a house.
Gan can paint a house in 9 days.
In 1 day, he paints 1/9 of a house.
Henry can paint a house in 10 days.
In 1 day, he paints 1/10 of a house.
If they work together, fraction of a house they can paint in 1 day = 1/6 + 1/9 + 1/10
= 15/90 + 10/90 + 9/90
= 34/90
= 17/45
(Lowest common multiple is 90, so change all the denominators to 90 first. Then simplify the resulting fraction)
Please note that the assumption here is that they don't take any breaks and there are no overlaps in their painting areas)
Number of days needed = 1 ÷ 17/45
= 45/17
= 2 11/17
Thank you so much
Thank you so much
Welcome
360 Tutoring Program