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Secondary 1 | Maths
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Date Posted: 3 years ago
Views: 339
Sum of exterior angles = 360°
For A, there are n exterior angles.
360° = n × a°
360° = an°
360 = an
Sum of interior angles
= 180° × (number of interior angles - 2)
= (number of interior angles) × (value of each interior angle)
For B, equate the two.
180° × (2n - 2) = 4½a° × 2n
360n° - 360° = 9an°
360n = 360 + 9an
Since you know from A that 360 = an,
360n = an + 9an
360n = 10an
a = 360n /10n
a = 36
Since 360 = an,
n = 360/a = 360/36 = 10
For A, there are n exterior angles.
360° = n × a°
360° = an°
360 = an
Sum of interior angles
= 180° × (number of interior angles - 2)
= (number of interior angles) × (value of each interior angle)
For B, equate the two.
180° × (2n - 2) = 4½a° × 2n
360n° - 360° = 9an°
360n = 360 + 9an
Since you know from A that 360 = an,
360n = an + 9an
360n = 10an
a = 360n /10n
a = 36
Since 360 = an,
n = 360/a = 360/36 = 10
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Date Posted:
3 years ago
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