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primary 6 | Maths
| Fractions
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Date Posted: 3 years ago
Views: 399
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Amy had $24.80 more than Beatty at first;
Beatty + $24.80 = Amy — (1)
After Beatty gave $14.20 to Amy, Amy had 3 times as much money as Beatty in the end;
Beatty - $14.20 = (Amy) / 3
3 (Beatty - $14.20) = Amy — (2)
(1) = (2)
Beatty + $24.80 = 3 (Beatty - $14.20)
= 3 Beatty - $42.60
3 Beatty - Beatty =$24.80 + $42.60
2 Beatty = $67.40
Beatty = $33.70
Beatty + $24.80 = Amy — (1)
After Beatty gave $14.20 to Amy, Amy had 3 times as much money as Beatty in the end;
Beatty - $14.20 = (Amy) / 3
3 (Beatty - $14.20) = Amy — (2)
(1) = (2)
Beatty + $24.80 = 3 (Beatty - $14.20)
= 3 Beatty - $42.60
3 Beatty - Beatty =$24.80 + $42.60
2 Beatty = $67.40
Beatty = $33.70
$33.70
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