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primary 6 | Maths
| Geometry
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Angle
Date Posted: 2 years ago
Views: 478
(b)
∠BEF = 90°- 38°=52° (Ans)
(a)
90°- 10°=80°
80°- 52°=28°
∠BFG = (180°- 28°)÷2=76° (Ans)
∠BEF = 90°- 38°=52° (Ans)
(a)
90°- 10°=80°
80°- 52°=28°
∠BFG = (180°- 28°)÷2=76° (Ans)
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