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Question
secondary 4 | A Maths
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Date Posted: 3 years ago
Views: 202
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y = x + 1/2x² = x + ½x-²
dy/dx = 1 + (-2)(½x-³) = 1 - 1/x³
At stationary point, dy/dx = 0
1 - 1/x³ = 0
1 = 1/x³
x³ = 1
x = ³√1 = 1
When x = 1, y = 1 + 1/2(1²) = 1 + 1/2 = 3/2
(Shown)
dy/dx = 1 + (-2)(½x-³) = 1 - 1/x³
At stationary point, dy/dx = 0
1 - 1/x³ = 0
1 = 1/x³
x³ = 1
x = ³√1 = 1
When x = 1, y = 1 + 1/2(1²) = 1 + 1/2 = 3/2
(Shown)
could you write on down on a piece of paper?
Later. Will upload
done
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Here.
Date Posted:
3 years ago
done
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Solution for part (ii) asap too !
Date Posted:
3 years ago
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