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primary 6 | Maths
| Fractions
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Date Posted: 2 years ago
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Cathy and Diana had 664 beads altogether. Cathy give away 24 beads and Diana gave away 3/5 of here beads then they have same number of beads left.
To find:
Number of beads had Cathy at first.
Suppose at first Cathy had x beads.
Since both Cathy and Diana had 664 beads altogether.
Therefore the number of beads had Diana at first are 664 - x.
When Cathy give away 24 beads and Diana gave away 3/5 of here beads then they have same number of beads left.
⇒ x - 24 = (664 - x) - 3/5(664 - x)
⇒ 5 (x - 24) = 5 (664 - x) - 3(664 - x)
⇒ 5x - 120 = 3320 - 5x - 1992 + 3x
⇒7x = 1448
⇒x = 206.86 ≈ 207
Therefore, at first Cathy had 206 beads.
To find:
Number of beads had Cathy at first.
Suppose at first Cathy had x beads.
Since both Cathy and Diana had 664 beads altogether.
Therefore the number of beads had Diana at first are 664 - x.
When Cathy give away 24 beads and Diana gave away 3/5 of here beads then they have same number of beads left.
⇒ x - 24 = (664 - x) - 3/5(664 - x)
⇒ 5 (x - 24) = 5 (664 - x) - 3(664 - x)
⇒ 5x - 120 = 3320 - 5x - 1992 + 3x
⇒7x = 1448
⇒x = 206.86 ≈ 207
Therefore, at first Cathy had 206 beads.
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