Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
secondary 3 | A Maths
One Answer Below
Anyone can contribute an answer, even non-tutors.
help pls
Date Posted: 2 years ago
Views: 195
Volume ratios can be compared directly just like mole ratios simply because we are only dividing and multiplying by the same value 24 all the time (thus cancelling the effects out)
In this case, based on the ratio 2 : 1 for carbon monoxide to oxygen, we find that 20 cm³ of carbon monoxide should react with 10 cm³ of oxygen, and just nice there is exactly 10 cm³ of oxygen as given in the question, so both the reactants are "equally limiting".
We can just take any of the values for the mole ratio comparison as a result.
Comparing the ratio 2 : 2 for carbon monoxide to carbon dioxide, volume of carbon dioxide formed is 20 cm³.
In this case, based on the ratio 2 : 1 for carbon monoxide to oxygen, we find that 20 cm³ of carbon monoxide should react with 10 cm³ of oxygen, and just nice there is exactly 10 cm³ of oxygen as given in the question, so both the reactants are "equally limiting".
We can just take any of the values for the mole ratio comparison as a result.
Comparing the ratio 2 : 2 for carbon monoxide to carbon dioxide, volume of carbon dioxide formed is 20 cm³.
See 1 Answer
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
The volume ratio is the same as the mole ratio for gases. There is no excess reactant, so 20cm³ CO2 is produced.
Date Posted:
2 years ago
360 Tutoring Program