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primary 6 | Maths
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Hi can someone help me please I need it by 6:00 tysm if u do!
Date Posted: 6 years ago
Views: 611
Richard completes: 1/6 of the lego set in 1 hr
Sam completes: 1/4 of the lego set in 1 hr
Tom completes: 1/3 of the lego set in 1 hr.
if they all work together, they can complete:
1/6 + 1/4 + 1/3 = 3/4 of the lego set in 1 hr
But the exercise didn't ask how much they can do per hour; it asked how long they'll take to finish one lego set, WORKING TOGETHER.
Time they will take is therefore:
1/ t per hour
where t stands for the time it takes to complete 1 lego set together.
This gives us an expression for their combined hourly rate. We already had a numerical expression for their combined hourly rate (3/4 per hour). So, setting these two expressions equal"
1/t = 3/4
You can solve by flipping the equation;
t/1 = 4/3
3t = 4
therefore
1t or t = 4/3 hours
Sam completes: 1/4 of the lego set in 1 hr
Tom completes: 1/3 of the lego set in 1 hr.
if they all work together, they can complete:
1/6 + 1/4 + 1/3 = 3/4 of the lego set in 1 hr
But the exercise didn't ask how much they can do per hour; it asked how long they'll take to finish one lego set, WORKING TOGETHER.
Time they will take is therefore:
1/ t per hour
where t stands for the time it takes to complete 1 lego set together.
This gives us an expression for their combined hourly rate. We already had a numerical expression for their combined hourly rate (3/4 per hour). So, setting these two expressions equal"
1/t = 3/4
You can solve by flipping the equation;
t/1 = 4/3
3t = 4
therefore
1t or t = 4/3 hours
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Hope it helps u
Date Posted:
6 years ago
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