Ask Singapore Homework?

Upload a photo of a Singapore homework and someone will email you the solution for free.



Question

primary 6 | Maths | Data Analysis
2 Answers Below

Anyone can contribute an answer, even non-tutors.

Answer This Question
Dan
Dan

primary 6 chevron_right Maths chevron_right Data analysis chevron_right Singapore

Help

Date Posted: 2 years ago
Views: 369

See 2 Answers

Method 2 (total unchanged)
Ratio of the number of 20¢ to 50¢ coins at first = 3 : 1
Value of every three 20¢ coins = 3 × 20¢ = 60¢
Value of every 50¢ coins = 50¢ × 1 = 50¢
At first,
Ratio of the value of the 20¢ coins to the 50¢ coins to their total value
= 60 : 50 : 110 = 6 : 5 : 11 = 12 : 10 : 22
Note that the total value is unchanged.
After the exchange, there is an equal value of 20¢ and 50 ¢ coins.
Now,
Ratio of the value of 20¢ to 50¢ coins to total
= 1 : 1 : 2 = 11 : 11 : 22
(Since the total value is unchanged, We make the total value to the same number for both ratios, 22)
Value of those twenty 20¢ coins Jenny exchanged = 20¢ × 20 = 400¢ (or $4)
So Jenny exchanged $4 worth of 20¢ coins for $4 for 50¢ coins.
Comparing the two ratios, we see that the value of 20¢ coins has decreased by 1 unit. The value of 50¢ coins has increased by 1 unit.
So 1 unit = $4
Value of 20¢ at first = 12 units
= 12 × $4 = $48
done {{ upvoteCount }} Upvotes
clear {{ downvoteCount * -1 }} Downvotes
J
J's answer
1022 answers (A Helpful Person)
Method 1
Value of those twenty 20¢ coins Jenny exchanged = 20¢ × 20 = 400¢ (or $4)
Number of 50¢ coins Jenny got from the neighbour in exchange = 400¢ ÷ 50¢ = 8
Since the value of each type of coin is the same after the the exchange,
2 × 50¢ = 100¢, 5 × 20¢ = 100¢
Every two 50¢ coins are equal in value to every five 20¢ coins.
Ratio of value of 20¢ to value of 50¢ now = 5 : 2
At first :
20¢ coins → 3 units, 50¢ coins →1 unit
Ratio of the number of 20¢ to 50¢ coins at first = 3 : 1 = 6 : 2
(We change to 6 : 2 to make division of the units easier. See the next working)
Following the ratio,
we let number of 50¢ coins at first be 2 units.
Number of 20¢ coins at first be 6 units.

Number of 50¢ coins now = 2 units + 8
Since the ratio of value of 20¢ to value of 50¢ now = 5 : 2,
Number of 20¢ coins now = (2 units + 8) ÷ 2 × 5
= (1 unit + 4) × 5
= 5 units + 20
Number of 20¢ coins at first = 5 units + 20 + 20
= 5 units + 40
But, we know that number of 20¢ coins at first = 6 units
So 5 units + 40 = 6 units
40 = 6 units - 5 units = 1 unit
Number of 20¢ coins at first = 6 units = 6 × 40 = 240
Value of 20¢ at first = 240 × 20¢ = 4800¢ = $48
done {{ upvoteCount }} Upvotes
clear {{ downvoteCount * -1 }} Downvotes
J
J's answer
1022 answers (A Helpful Person)