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secondary 4 | A Maths
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need help with this qn, pls explain too
= - 1 / -(x - 4)
= 1/(x - 4)
So,
3/(x - 4)² - 1/(4 - x)
= 3/(x - 4)² + 1/(x - 4)
Now you can make the denominator the same.
= 3/(x - 4)² + (x - 4)/(x - 4)²
= (3 + x - 4)/(x - 4)²
= (x - 1)/(x - 4)²
= 3/(x - 4)^2 + 1/(x - 4)
= 3/(x - 4)^2 + (x - 4)/(x - 4)(x - 4)
= 3/(x - 4)^2 + (x - 4)/(x - 4)^2
= [3 + x - 4]/(x - 4)^2
= (x - 1)/(x - 4)^2
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