Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
Secondary 1 | Maths
One Answer Below
Anyone can contribute an answer, even non-tutors.
Please help asap!!
Date Posted: 2 years ago
Views: 166
See 1 Answer
A) Perimeter of semi circle formula: π × r
π : 22/7
R : 22 / 2 = 11cm
Perimeter of semi circle (CDE) = 22/7 X 11= 34.5714
BC = FE
= 55 - 12 - 11
= 32cm
AB = GF = 15cm
AG = 40cm
Total perimeter = AG + AB + GF + BC + FE + CDE = 40 + 15 + 15 + 32 + 32 + 34.5714
= 168.5714
~ 168.571cm (3 Sig. Fig.)
B) Area of semi circle (CDE) = π X r^2 X 1/2
= 22/7 X 11^2 X 1/2
= 190.14285cm^2
Area of rectangular (BCEF) = B X W
= 22 X 32
= 704cm^2
Area of trapezium (ABFG) = 1/2h (AG + BF)
= 1/2 X 12 X (40 + 22)
= 372cm^2
Total area = area (CDE + BCEF + ABFG)
= 190.14285 + 704 + 372
= 1266.14285
~ 1266.142cm^2 (3 Sig. Fig.)
π : 22/7
R : 22 / 2 = 11cm
Perimeter of semi circle (CDE) = 22/7 X 11= 34.5714
BC = FE
= 55 - 12 - 11
= 32cm
AB = GF = 15cm
AG = 40cm
Total perimeter = AG + AB + GF + BC + FE + CDE = 40 + 15 + 15 + 32 + 32 + 34.5714
= 168.5714
~ 168.571cm (3 Sig. Fig.)
B) Area of semi circle (CDE) = π X r^2 X 1/2
= 22/7 X 11^2 X 1/2
= 190.14285cm^2
Area of rectangular (BCEF) = B X W
= 22 X 32
= 704cm^2
Area of trapezium (ABFG) = 1/2h (AG + BF)
= 1/2 X 12 X (40 + 22)
= 372cm^2
Total area = area (CDE + BCEF + ABFG)
= 190.14285 + 704 + 372
= 1266.14285
~ 1266.142cm^2 (3 Sig. Fig.)
Tku!
360 Tutoring Program