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secondary 4 | A Maths
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How to do (iv) and (v)?
Date Posted: 3 years ago
Views: 480
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done
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clear
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to be more accurate its 0<=t<1.5 since time cant be negative
Date Posted:
3 years ago
One more thing, I didn't test whether that t corresponded to max or min, but its obvious from the expression that if I differentiated further, the 2nd derivative being 12 (positive) implies a min value.
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