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Secondary 1 | Maths
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revision exercise
Date Posted: 3 years ago
Views: 414
1. cross multiply
11(2a-3b) = 7(a+b)
22a-33b = 7a+7b
15a = 40b
b = (15/40)a = (3/8)a
5b/8a = (5*(3/8)a)/8a = 15/64
2.
let: #of 20-cent coins = a
# of 50-cent coins = b
a+b = 54
20a+50b=2070
2a+5b=207
2a+5b = 207
2a+2b = 108
----------------- minus
3b = 99
b = 33
a = 21
11(2a-3b) = 7(a+b)
22a-33b = 7a+7b
15a = 40b
b = (15/40)a = (3/8)a
5b/8a = (5*(3/8)a)/8a = 15/64
2.
let: #of 20-cent coins = a
# of 50-cent coins = b
a+b = 54
20a+50b=2070
2a+5b=207
2a+5b = 207
2a+2b = 108
----------------- minus
3b = 99
b = 33
a = 21
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Hi, hope this helps. Please let me know if there is any mistake:)
Date Posted:
3 years ago
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