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primary 6 | Maths
| Data Analysis
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Date Posted: 2 years ago
Views: 199
5-1=4
92÷4=23
2×23×0.1+9.2=13.8
92÷4=23
2×23×0.1+9.2=13.8
See 1 Answer
1 50⊄ coin → $0.40 more than 1 10⊄ coin
$9.20 → 9.20÷0.40 = 23 coins
Therefore, total have
23 50⊄ coins and
23 10⊄ coins
Total value
= 23 × $0.5 + 23× $0.10
= $11.50 + $2.30
= $13.80
$9.20 → 9.20÷0.40 = 23 coins
Therefore, total have
23 50⊄ coins and
23 10⊄ coins
Total value
= 23 × $0.5 + 23× $0.10
= $11.50 + $2.30
= $13.80
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