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primary 5 | Maths
| Angles & Geometry
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Teachers, can help me how to find angle X?
Date Posted: 2 years ago
Views: 412
Recall that opposite angles of a parallelogram are equal in measure.
So , ∠ QRS = 55°
(or ∠QRB = 55°. RS is just an extension of RB)
∠x = 180° - 55° - 63° (angle sum of △BRQ)
= 62°
So , ∠ QRS = 55°
(or ∠QRB = 55°. RS is just an extension of RB)
∠x = 180° - 55° - 63° (angle sum of △BRQ)
= 62°
Or ,
∠PQR = 180° - 55° = 125°
(adjacent angles of a parallelogram add up to 180)
Or
(Angles between parallel lines add up to 180°)
∠x = 125° - 63° = 62°
∠PQR = 180° - 55° = 125°
(adjacent angles of a parallelogram add up to 180)
Or
(Angles between parallel lines add up to 180°)
∠x = 125° - 63° = 62°
Thank you for explaining.
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Hope this helps
Date Posted:
2 years ago
Thank you much.
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