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Secondary 1 | Maths
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Pls help. I need the explanation also .
15 × 15 = 225
Hence,
1+3+5+7+9+11+13+15+17+19+21+23+25+27+29 = 225
n = 29
Or
15×2 -1 =29
If we take the square root of 200, we get 14.14. Upon closer inspection, 14^2 gives 196 (^ represents to the power of) while 15^2 gives 225.
We can see by inspection that we need the row which contains … = 225 = 15 x 15.
Upon inspection, we see that we need the first 15 numbers in the pattern 1 + 3 + 5 + …, and if you list out everything, 15th term will be 29.
1, 3, 5, 7, 9,
11, 13, 15, 17, 19,
21, 23, 25, 27, 29
So, we have the line 1 + 3 + 5 + … + 27 + 29 = 225 = 15 x 15, and therefore n = 29.
The latter causes the former.
Square rooting the perfect square gives back the integer.
Square rooting to get integer is the reverse of the result, not the cause of it.
Based on the pattern, we can deduce that :
1 + 3 + 5 + 7 + 9 +... + n = k² , where is a integer
So when 1 + 3 + 5 + 7 + 9 +... + n > 200 ,
k² > 200
k > √200 (since n is positive, we do not consider the negative square root)
k > 14.14 (4.sf)
Least value of k = 15 since 15 is the smallest integer bigger than it.
Next, from the pattern we can see that there are k odd numbers for the kth row.
(In other words, the number of odd numbers in each row is the same as the row number)
We observe that the last number, n equals to 2k - 1
Eg.
1
3 = 2(2) - 1
5 = 2(3) - 1
7 = 2(4) - 1
9 = 2(5) - 1
So n = 2k - 1
So least value of n
= 2(15) - 1
= 30 - 1
= 29
Alternatively,
k > √200
2k > 2√200
2k - 1 > 2√200 - 1
2k - 1 > 27.28
n > 27.28
Since n is odd, least value of n = 29
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