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secondary 4 | A Maths
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Hi is the above statement true pls help thank u
Date Posted: 3 years ago
Views: 353
dx/dt = 4
Integrating back with respect to t,
x = 4t + c, c is a constant.
So,
4t = x - c
t = ¼x - ¼c
dt/dx = ¼
So, yes. True.
Integrating back with respect to t,
x = 4t + c, c is a constant.
So,
4t = x - c
t = ¼x - ¼c
dt/dx = ¼
So, yes. True.
Thanks!!
See 1 Answer
Answered in main comments.
Another way to think about it :
If dx/dt = 4, it can be taken to mean that as t increases at a certain rate/by a certain amount, x increases by 4 times of that rate/amount.
So reciprocally, t increases at ¼ the rate of x increasing.
Another way to think about it :
If dx/dt = 4, it can be taken to mean that as t increases at a certain rate/by a certain amount, x increases by 4 times of that rate/amount.
So reciprocally, t increases at ¼ the rate of x increasing.
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