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secondary 4 | E Maths
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Any way to solve this question (2 points) without trial-and-error?
Date Posted: 3 years ago
Views: 201
This is actually an overload of data question. Any extra data may conflict with or contradict the other values.
For example, if we take 9 cm, 10 cm and 40 degrees to be correct values, we can calculate BC to be roughly 6.566 cm, but the data 8 cm conflicts with this.
Whichever set of three data values are correct, there will always be the fourth one which does not agree with the other values.
For example, if we take 9 cm, 10 cm and 40 degrees to be correct values, we can calculate BC to be roughly 6.566 cm, but the data 8 cm conflicts with this.
Whichever set of three data values are correct, there will always be the fourth one which does not agree with the other values.
Imagine a right angled triangle with sides given as 2 cm, 6 cm and 7 cm and the question asks us to find one of the other two angles. What if these three numbers do not follow the Pythagoras' Theorem even though the "question" has stated that the triangle is right-angled?
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done
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Hello, apart from your convention formula of 1/2*b*h to find the area of triangle, you can use the formula 1/2*b*c*sinA (which can be found in your formula list if I'm not wrong).
The answer I got is 28.9cm²
The answer I got is 28.9cm²
Date Posted:
3 years ago
The question is actually about having too much data in a question, and this actually backfires in this situation as the fourth value of BC = 8 cm seems incorrect.
1/2x9x10xsin40
The question is actually about having too much data in a question, and this actually backfires in this situation as the fourth value of BC = 8 cm seems incorrect.
U good bro?
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