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secondary 4 | E Maths
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Date Posted: 3 years ago
Views: 518
Mr. Tan is 4 times as old as his son Dawei:
T = 4D
Mrs. Tan is 5 times as old as her daughter Limei:
M = 5L
Sum of ages of all 4 family members:
T+M+D+L = 92
4D + 5L + D + L =92
5D + 6L = 92
4 yrs ago, Dawei was twice as old as Limei:
D-4 = 2(L-4)
D-4=2L-8
2L - D = 4
D = 2L-4
5(2L-4) + 6L = 92
10L - 20 + 6L = 92
16L = 112
L = 112/16 = 7
L = 7
D = 2L-4 = 10
Dawei is 10 yrs old and Limei is 7 yrs old now.
T=4*10 = 40
M = 5*7 = 35
D=10
L=7
T+M+D+L = 40+35+10+7 = 92
D-4 = 2(L-4)
10-4 = 2(7-4)
6=6
T = 4D
Mrs. Tan is 5 times as old as her daughter Limei:
M = 5L
Sum of ages of all 4 family members:
T+M+D+L = 92
4D + 5L + D + L =92
5D + 6L = 92
4 yrs ago, Dawei was twice as old as Limei:
D-4 = 2(L-4)
D-4=2L-8
2L - D = 4
D = 2L-4
5(2L-4) + 6L = 92
10L - 20 + 6L = 92
16L = 112
L = 112/16 = 7
L = 7
D = 2L-4 = 10
Dawei is 10 yrs old and Limei is 7 yrs old now.
T=4*10 = 40
M = 5*7 = 35
D=10
L=7
T+M+D+L = 40+35+10+7 = 92
D-4 = 2(L-4)
10-4 = 2(7-4)
6=6
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