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primary 6 | Maths
| Speed
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Date Posted: 3 years ago
Views: 700
Every ⅓ Charles traveled, Tony is 15 km ahead.
Therefore, when Charles traveled ³/3.
Tony is 45 km ahead.
90 km → 1 hour
45 km → ½ hour.
Therefore, Charles reached at 9: 35 + ½ hour = 10:05 am.
Therefore, when Charles traveled ³/3.
Tony is 45 km ahead.
90 km → 1 hour
45 km → ½ hour.
Therefore, Charles reached at 9: 35 + ½ hour = 10:05 am.
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