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secondary 4 | A Maths
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Hi please assist TIA! :)
N is the number of germs at first.
After 1 minute, 21% of germs are killed. So 79% of germs are left alive.
79% = 79/100 = 0.79
So number of germs after 1 minute
= 0.79N
(this is the same as saying 79/100 of N or 79% of N)
Now let's say another minute passes. Again, 21% of the remaining 0.79N germs are killed. 79% are left alive.
Number of germs after 2 minutes
= 0.79 (0.79N)
= (0.79)²N
Likewise,after 3 minutes,
0.79(0.79)²N = (0.79)³N
After 4 minutes,
0.79(0.79)³N = (0.79)⁴N
And so on.
The power/index of 0.79 in the expression is always the same as the number of minutes that have passed.
So , after n minutes
Number of germs left = (0.79)ⁿN
So after 20 minutes,
Number of germs left = (0.79)²⁰N
≈ 0.00896N
Percentage of germs left
= Number of germs left ÷ total number of germs at first × 100%
= 0.00896N / N × 100%
= 0.896%
Percentage of germs killed
= 100% - 0.896%
= 99.104%
= 99% (2s.f)
So x = 99
We already know (0.79)ⁿN is the number of germs left after n minutes. So equate this to Neᵏⁿ
(0.79)ⁿN = Neᵏⁿ
(0.79)ⁿ = eᵏⁿ ( or (eᵏ)ⁿ )
Since the index/power is the same for both single terms on the left and right hand side, comparing both bases,
0.79 = eᵏ
k = ln 0.79
k ≈ -0.23572
k = -0.236 (3s.f)
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