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secondary 4 | A Maths
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Yang li shuang
Yang Li Shuang

secondary 4 chevron_right A Maths chevron_right Singapore

Hi pls help with qn 16. Thanks alot!

Date Posted: 2 years ago
Views: 294
J
J
2 years ago
cos⁶θ + sin⁶θ

= (cos²θ)³ + (sin²θ)³

= (cos²θ + sin²θ)( (cos²θ)² - cos²θsin²θ + (sin²θ)² )


(Recall the property a³ + b³ = (a + b)(a² - ab + b²) )

= (1)( (cos²θ)² + 2cos²θsin²θ + (sin²θ)² - 3cos²θsin²θ)


(Completing the square, + recall cos²A + sin²A = 1)

= (cos²θ + sin²θ)² - 3(sinθcosθ)²

= 1² - 3(½sin2θ)²

(Recall sin2A = 2sinAcosA, so sinAcosA = ½sin2A)

= 1 - ¾sin²2θ

= (8 - 6 sin²2θ) / 8

= (5 + 3(1 - 2sin²2θ)) / 8

= (5 + 3cos4θ)/8 (proved)

(Recall cos 2A = 1 - 2sin²A = cos²A - sin²A = 2cos²A - 1. Here your A = 2θ)
Eric Nicholas K
Eric Nicholas K
2 years ago
You actually succeeded in finding the symbol for power 6.

I only know power 2 and 3, but I have no idea how to input higher powers.
J
J
2 years ago
Google keyboard for Android has ¹²³⁴ only.

Other superscripts and subscripts can be easily generated online (there are plenty of sites that do this)

You can even copy and paste from the search results.

Eg. Google 'superscript 6'


So it's a matter of effort. Using ^ to represent superscript just makes things less clear and confusing.
Yang li shuang
Yang Li Shuang
2 years ago
Thank you so much, you are really helpful! This helps a lot!

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Eric Nicholas K
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5997 answers (Tutor Details)
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This one is a little long-winded and requires knowledge from both Trigo and algebra.
Eric Nicholas K
Eric Nicholas K
2 years ago
Sorry, I just realised that my picture got partially cut off, you must click on the picture for the full view
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sstrike
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J
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