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primary 6 | Maths | Speed
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CJ
CJ

primary 6 chevron_right Maths chevron_right Speed chevron_right Singapore

Pls help. Thks.

Date Posted: 2 years ago
Views: 378
AC Lim
AC Lim
2 years ago
If you don't want solve with ratio..
Here are my working.
Lorry start at 6.00am while car start 2 hour later.
So, Lorry already at 2h × 50 km/h = 100 km ahead.

Speed difference between car and lorry
= 90-50
= 40 km/h
It mean every 1 h car is 40km closer to lorry.

40km→ 1h
100km → 100÷40 = 2.5 h
a) Car over take lorry at 8.00am + 2.5h (2h 30min)
= 10.30 am.

b) Total time taken by car
=2.5 + 2
= 4.5h
Distance
= 4.5 × 90
= 405 km.

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sstrike
Sstrike's answer
5364 answers (A Helpful Person)
Lorry start at 6.00am while car start 2 hour later.
So, Lorry already at 2h × 50 km/h = 100 km ahead.

Speed difference between car and lorry
= 90-50
= 40 km/h
It mean every 1 h car is 40km closer to lorry.

40km→ 1h
100km → 100÷40 = 2.5 h
a) Car over take lorry at 8.00am + 2.5h (2h 30min)
= 10.30 am.

b) Total time taken by car
=2.5 + 2
= 4.5h
Distance
= 4.5 × 90
= 405 km
done {{ upvoteCount }} Upvotes
clear {{ downvoteCount * -1 }} Downvotes
AC Lim
Ac Lim's answer
12338 answers (A Helpful Person)