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secondary 4 | A Maths
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Hi all, please help me with part c. I cant seem to get the answer
Date Posted: 2 years ago
Views: 219
16c i mean
What is the given answer?
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Thanks i got it. But just a question though, from the equation that you got:
tan3x + tan3x(tan2x)^2 = 0
Therefore, tan3x = -tan3x(tan2x)^2
so why cant I divide both sides by tan 3x here.
tan3x + tan3x(tan2x)^2 = 0
Therefore, tan3x = -tan3x(tan2x)^2
so why cant I divide both sides by tan 3x here.
Because you will lose solutions arising from tan 3x = 0.
It’s a typical type of idea which applies to questions like
x^2 = 5x
x = 0 and x = 5 satisfy this equation, but if we divide both sides by x, we only get the solution x = 5.
In other words, a correct approach is to first bring it over into x^2 - 5x = 0 before factorising it into x (x - 5) = 0.
In the other approach, the solution x = 0 is lost in the transition because we “divided a solution away”.
It’s a typical type of idea which applies to questions like
x^2 = 5x
x = 0 and x = 5 satisfy this equation, but if we divide both sides by x, we only get the solution x = 5.
In other words, a correct approach is to first bring it over into x^2 - 5x = 0 before factorising it into x (x - 5) = 0.
In the other approach, the solution x = 0 is lost in the transition because we “divided a solution away”.
Got it, Thanks!
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