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primary 6 | Maths
| Data Analysis
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Please help me in this question. Thanks.
Date Posted: 2 years ago
Views: 560
Answer: 10:40 am
Going down the multiplication of 8, the smallest number divisible by 5 would be 40 (8 * 5).
5. 10. 15............35. 40. 45..........75.80...
8. 16. 24............31. 40. 48..........72.80...
You will realised number of minute pass 10am in which both alarm will ring would be divisible by both 5 and 8.
The easiest method would be multiplying both numbers first, which in our case is 8*5, THEN check if any other values lower than that is divisible by both numbers.
Going down the multiplication of 8, the smallest number divisible by 5 would be 40 (8 * 5).
5. 10. 15............35. 40. 45..........75.80...
8. 16. 24............31. 40. 48..........72.80...
You will realised number of minute pass 10am in which both alarm will ring would be divisible by both 5 and 8.
The easiest method would be multiplying both numbers first, which in our case is 8*5, THEN check if any other values lower than that is divisible by both numbers.
Thanks.
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