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Part (a); I found the general expression for Tn, where n is the nth term of the series. This is not necessary at this part, but it helps solve the qn quickly, and it is later used in part (c)
My explanation in (b) is lengthy as it is meant to aid your understanding, pls dun submit such an essay in your assignments/exams, there are much better and faster ways of answering the qn
My explanation in (b) is lengthy as it is meant to aid your understanding, pls dun submit such an essay in your assignments/exams, there are much better and faster ways of answering the qn
Date Posted:
3 years ago
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Cont'd from my answer
Part (c) is just finding the pattern that is consistent in all the terms. Takes a little creativity, else it shouldn't pose problems.
(d) try to solve this part even if u can't do any of the other parts, as the expression required has already been given by the qn in (c), where they asked u to *show* the expression. With the expression, it becomes a simple matter of subbing in values.
(e) This is linked to (d), as u would've solved for the difference between 2 arbitrary terms Tp & Tp+1. Using the expression derived, you realise that there is a minimum value for the difference between 2 adjacent terms, as n has a certain range of values restricting it too.
Hope this helps
Part (c) is just finding the pattern that is consistent in all the terms. Takes a little creativity, else it shouldn't pose problems.
(d) try to solve this part even if u can't do any of the other parts, as the expression required has already been given by the qn in (c), where they asked u to *show* the expression. With the expression, it becomes a simple matter of subbing in values.
(e) This is linked to (d), as u would've solved for the difference between 2 arbitrary terms Tp & Tp+1. Using the expression derived, you realise that there is a minimum value for the difference between 2 adjacent terms, as n has a certain range of values restricting it too.
Hope this helps
Date Posted:
3 years ago