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primary 6 | Maths
| Fractions
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Please help. Thank you
Date Posted: 3 years ago
Views: 523
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there is a standard method of solving these kinds of questions, just make the numerator the same.
why this works: try adding a box into this problem. The box is 2/5 of Henry’s mass, and 3/4 of Ian’s mass. But the weight of the box is constant.
Hence by manipulating the fractions to say that the box is 6/15 of Henry’s mass and 6/8 of Ian’s mass, you can derive that ratio of Henry’s to Ian’s mass is 15:8.
Henry’s mass/ mass of both boys = 15/(15+8) = 15/23 (cannot be simplified further as 23 is a prime number)
hope this helps:))
why this works: try adding a box into this problem. The box is 2/5 of Henry’s mass, and 3/4 of Ian’s mass. But the weight of the box is constant.
Hence by manipulating the fractions to say that the box is 6/15 of Henry’s mass and 6/8 of Ian’s mass, you can derive that ratio of Henry’s to Ian’s mass is 15:8.
Henry’s mass/ mass of both boys = 15/(15+8) = 15/23 (cannot be simplified further as 23 is a prime number)
hope this helps:))
May I check how you get 6/15 & 6/8 from 2/5 & 3/4?
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