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primary 6 | Maths
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Date Posted: 2 years ago
Views: 422
Q1: 1713 hr
Ali at ⅓ of journey, Benny is 4.8 km ahead.
Therefore, when Ali completed whole journey, 3/3, Benny is 4.8×3 = 14.4km ahead.
Time to travel 14.4km by Benny = ?
18 km → 1hr or 60 min
14.4 km = 14.4÷18 = 0.8 hr or 48mins
Therefore,
Ali reached at 1625 + 48 min = 1713 hr
Ali at ⅓ of journey, Benny is 4.8 km ahead.
Therefore, when Ali completed whole journey, 3/3, Benny is 4.8×3 = 14.4km ahead.
Time to travel 14.4km by Benny = ?
18 km → 1hr or 60 min
14.4 km = 14.4÷18 = 0.8 hr or 48mins
Therefore,
Ali reached at 1625 + 48 min = 1713 hr
Q2.
Distance between town A and Town B
= 75× 6
= 450 km
a) James took 6hr reached at 8.00pm.
Therefore, James start at 2.00pm, so Lisa start at 3.00pm cause James started 1 hr earlier.
b) When James reached at 8.00pm, Lisa traveled for 5 hr. (8.00-5hr = 3.00pm).
Lisa, traveled distance = 80 × 5 = 400km.
Therefore, Lisa left = 450-400 = 50km from town B.
Distance between town A and Town B
= 75× 6
= 450 km
a) James took 6hr reached at 8.00pm.
Therefore, James start at 2.00pm, so Lisa start at 3.00pm cause James started 1 hr earlier.
b) When James reached at 8.00pm, Lisa traveled for 5 hr. (8.00-5hr = 3.00pm).
Lisa, traveled distance = 80 × 5 = 400km.
Therefore, Lisa left = 450-400 = 50km from town B.
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Hope this helps.
Date Posted:
2 years ago
Thank you so much!!
Thank you so much!!
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