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secondary 2 | Maths
2 Answers Below
Anyone can contribute an answer, even non-tutors.
Please help. Thank you.
Date Posted: 3 years ago
Views: 216
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Let x be the ten place digit,
Y be the one place digit:
In other words, if the number is 56,
x is 5 (not 50), y is 6
First statement:
X = 2y + 1 ----(1)
Second statement:
10x + y = x + 10y + 36 (the tenth place need x10)
9x = 9y + 36 ----(2)
Sub (1) into (2):
9(2y + 1) = 9y + 36
18y + 9 = 9y + 36
9y = 27
y = 3
Sub into (1):
X = 7
:. The original value is 73//
Y be the one place digit:
In other words, if the number is 56,
x is 5 (not 50), y is 6
First statement:
X = 2y + 1 ----(1)
Second statement:
10x + y = x + 10y + 36 (the tenth place need x10)
9x = 9y + 36 ----(2)
Sub (1) into (2):
9(2y + 1) = 9y + 36
18y + 9 = 9y + 36
9y = 27
y = 3
Sub into (1):
X = 7
:. The original value is 73//
Could u please explain why the tens place need to x10? Still very confused
Consider from the number: 73
X will be 7, Y will be 3.
So 73 is (10x + y)
If u flip the number,
The number becomes 37:
(x still 7, y still 3)**
So 37 is (10y + x)
The number represented by X and Y only represents the number in their POSITION,
Not the actual value which is 70, but ONLY 7.
But when u take into account the whole value,
U have to multiply by 10 for "tens place"
X will be 7, Y will be 3.
So 73 is (10x + y)
If u flip the number,
The number becomes 37:
(x still 7, y still 3)**
So 37 is (10y + x)
The number represented by X and Y only represents the number in their POSITION,
Not the actual value which is 70, but ONLY 7.
But when u take into account the whole value,
U have to multiply by 10 for "tens place"
Thank you so much.
done
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Hope this helps!
Date Posted:
3 years ago
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