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primary 6 | Maths
| Ratio
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Date Posted: 3 years ago
Views: 364
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I used the unitary method
Since Mary is the base(100%), that means Raymond must have 150% stickers. I think so...
Add the total number of units for P, R and J then x the value of 1 unit
Since Mary is the base(100%), that means Raymond must have 150% stickers. I think so...
Add the total number of units for P, R and J then x the value of 1 unit
Date Posted:
3 years ago
done
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Look for repeated identity. (1) Jimmy is repeated, the units should the same. It happens that here Jimmy with Paul or with Mary, he has 2 units. No need to adjust. Check Mary(2). Mary is 2 units compared with Raymond, 5 units when compared with Jimmy. Smallest common multiple of 2 and 5 is 10, so make units of Mary 10 at the end. After,adjust other affected units belonging to other children.
Date Posted:
3 years ago
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