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primary 6 | Maths
| Algebra
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Date Posted: 3 years ago
Views: 413
16 x $0.20 = $3.20
$29.80 - $3.20 = $26.60
After we minus the excess 20-cent coins, there are an equal number of 20 and 50 cent coins that adds up to $26.60. So to find the number of sets of 20 and 50 cent coins, we take
$26.60 / $0.70 = 38
There are 38 Sets of ($0.20 + $0.50). So there is also 38 50-Cents coins.
$29.80 - $3.20 = $26.60
After we minus the excess 20-cent coins, there are an equal number of 20 and 50 cent coins that adds up to $26.60. So to find the number of sets of 20 and 50 cent coins, we take
$26.60 / $0.70 = 38
There are 38 Sets of ($0.20 + $0.50). So there is also 38 50-Cents coins.
Thank you
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16 x $0.20 = $3.20
$29.80 - $3.20 = $26.60
After we minus the excess 20-cent coins, there are an equal number of 20 and 50 cent coins that adds up to $26.60. So to find the number of sets of 20 and 50 cent coins, we take
$26.60 / $0.70 = 38
There are 38 Sets of ($0.20 + $0.50). So there is also 38 50-Cents coins.
$29.80 - $3.20 = $26.60
After we minus the excess 20-cent coins, there are an equal number of 20 and 50 cent coins that adds up to $26.60. So to find the number of sets of 20 and 50 cent coins, we take
$26.60 / $0.70 = 38
There are 38 Sets of ($0.20 + $0.50). So there is also 38 50-Cents coins.
Date Posted:
3 years ago
Thank you
Thank you
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