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secondary 3 | A Maths
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question7. urgent, mom is finding me soon. thanks a ton.
Date Posted: 2 years ago
Views: 452
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2 log5 (x) - log5 (x-8) = 2
Log5 (x^2) - log5 (x-8) = 2 (Power Rule)
Log5 (x^2 / (x-8)) = 2 (Quotient Rule)
X^2 / (x-8) = 5^2
x^2 = 25(x-8)
x^2 = 25x - 200
x^2 - 25x + 200 = 0
check discriminant, D
D = B^2 - 4AC
= (-25)(-25) - 4 (1)(200)
= -175 < 0
D <0
:. There's no real soln //
Log5 (x^2) - log5 (x-8) = 2 (Power Rule)
Log5 (x^2 / (x-8)) = 2 (Quotient Rule)
X^2 / (x-8) = 5^2
x^2 = 25(x-8)
x^2 = 25x - 200
x^2 - 25x + 200 = 0
check discriminant, D
D = B^2 - 4AC
= (-25)(-25) - 4 (1)(200)
= -175 < 0
D <0
:. There's no real soln //
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