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Question
primary 6 | Maths
| Fractions
3 Answers Below
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Pls help
Date Posted: 3 years ago
Views: 512
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https://ask.manytutors.com/questions/103590
Date Posted:
3 years ago
Not really understand the answer.
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Alternative
Date Posted:
3 years ago
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alternative
S → B:G = 3u : 2u
NS → B:G = 20 : 170
4×(3u+20) = 2u+170
u = (170-4×20)÷(4×3-2) = 9
2u+170 = 2×9+170 = 188 (Ans)
S → B:G = 3u : 2u
NS → B:G = 20 : 170
4×(3u+20) = 2u+170
u = (170-4×20)÷(4×3-2) = 9
2u+170 = 2×9+170 = 188 (Ans)
Date Posted:
3 years ago
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