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The purpose of multiplying the equations in the first step is essentially like using the elimination method when solving simultaneous right?
Yes. Easy to use elimination method in complex number than substitution method...
May i clarify why arg(u) is 0?
Not 0, is detta..
Polar form: re^(i detta)= r[cos(detta)+i sin(detta)]
oh right, it is arg(sin(θ)) that is 0. thanks
sin(detta) is a purely real number. Given 0