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primary 6 | Maths
| Algebra
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Supposition question
For those 12 correctly answered questions, he would score :
12 × 6 points = 72 points
So for the other 8 questions,
72 - 68 = 4
He would have been deducted a total of 4 points and obtained an overall score of 68.
if we pair every wrongly answered question with an unanswered question,
2 points are scored for the unanswered one but 3 points are deducted for the wrongly answered one.
So there would be an overall deduction of 1 point.
For 4 such pairs, that would be :
4 x 1 = 4
There would be a deduction of 4 points. And 4 such pairs means 8 questions in total, which fits the remaining number of questions.
So there were 4 unanswered questions.
① Assume all 8 questions were unanswered.
Number of points scored here
= 8 × 2
= 16
② Since there must be an overall deduction of 4 points from these questions, we need to change some of these to wrongly answered questions.
For every one unanswered question changed, the 2 points awarded must be taken back. Another 3 points must be deducted since it is now a wrongly answered question.
2 + 3 = 5
For each question changed, 5 points are removed.
③ 16 + 4 = 20
So in order to have an overall deduction of 4 marks, 20 marks must be removed.
④ 20 ÷ 5 = 4
So 4 questions have to be changed. Which means there were 4 wrongly answered questions in the first place.
⑤ 8 - 4 = 4
There were 4 questions unanswered.
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