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Question
primary 6 | Maths
| Measurement
One Answer Below
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Date Posted: 3 years ago
Views: 409
a)
Length = 2 × 22 = 44
Volume water of tank A
= 22 × 44 × 9
= 8712 cm³
Therefore, volume water in Tank B
= 10230 - 8712
= 1518 cm³ (or ml)
Tank B is ⅔ fill = 1518
44 × Length × ⅔×9 = 1518
Length = 1518 ÷ 44 ÷ 6 = 5.75cm
Volume of tank B
= 5.75×44×9
= 2277 cm³
Or
⅔ → 1518
³/3 → 1518×3÷2 = 2277cm³
Length = 2 × 22 = 44
Volume water of tank A
= 22 × 44 × 9
= 8712 cm³
Therefore, volume water in Tank B
= 10230 - 8712
= 1518 cm³ (or ml)
Tank B is ⅔ fill = 1518
44 × Length × ⅔×9 = 1518
Length = 1518 ÷ 44 ÷ 6 = 5.75cm
Volume of tank B
= 5.75×44×9
= 2277 cm³
Or
⅔ → 1518
³/3 → 1518×3÷2 = 2277cm³
See 1 Answer
a)
Length = 2 × 22 = 44
Volume water of tank A
= 22 × 44 × 9
= 8712 cm³
Therefore, volume water in Tank B
= 10230 - 8712
= 1518 cm³ (or ml)
Tank B is ⅔ fill = 1518
44 × Length × ⅔×9 = 1518
Length = 1518 ÷ 44 ÷ 6 = 5.75cm
Volume of tank B
= 5.75×44×9
= 2277 cm³
Or
⅔ → 1518
³/3 → 1518×3÷2 = 2277cm³
Length = 2 × 22 = 44
Volume water of tank A
= 22 × 44 × 9
= 8712 cm³
Therefore, volume water in Tank B
= 10230 - 8712
= 1518 cm³ (or ml)
Tank B is ⅔ fill = 1518
44 × Length × ⅔×9 = 1518
Length = 1518 ÷ 44 ÷ 6 = 5.75cm
Volume of tank B
= 5.75×44×9
= 2277 cm³
Or
⅔ → 1518
³/3 → 1518×3÷2 = 2277cm³
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