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secondary 2 | Maths
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pls help with q12, i have math exam tomorrow thank you
Date Posted: 3 years ago
Views: 546
Your part a) is correct.
Notice that 31408 has a 3, a 14 and a 8.
This is similar to 3x² + 14x + 8
So rewrite the number as a sum first.
31408 = 30000 + 1400 + 8
Then you factor out those numbers.
= 3(10000) + 14(100) + 8
We have x² so rewrite 10000 as 100²
(10000 = 100 × 100. In fact, seeing the 100 next to 14 is already a clue to substitute x = 100)
= 3(100²) + 14(100) + 8
Use the substitution accordingly
= (3(100) + 2)(100 + 4)
= (302)(104)
These are two factors of 31408
Notice that 31408 has a 3, a 14 and a 8.
This is similar to 3x² + 14x + 8
So rewrite the number as a sum first.
31408 = 30000 + 1400 + 8
Then you factor out those numbers.
= 3(10000) + 14(100) + 8
We have x² so rewrite 10000 as 100²
(10000 = 100 × 100. In fact, seeing the 100 next to 14 is already a clue to substitute x = 100)
= 3(100²) + 14(100) + 8
Use the substitution accordingly
= (3(100) + 2)(100 + 4)
= (302)(104)
These are two factors of 31408
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