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primary 6 | Maths
| Ratio
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Date Posted: 3 years ago
Views: 292
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A)
Total Length = 120 * 5 = 600
Since Average of A B C is 20 more than Average of D E
Take 600 - 20 * 3 = 540 (5 average units)
1 unit = 540 / 5 = 108
Hence 1 set of possible length:
D = 108cm, E = 108cm //
(A B C can be 108 + 20 = 128cm each)
B) total length of D+ E = 108 * 2 = 216cm
D : 1 unit + 16 cm
E : 1 unit - 20 cm
2 unit = 216 - 16 + 20 = 220cm
1 unit = 110cm
:. Length of D = 110 + 16 = 126cm //
(E = 90cm)
Total Length = 120 * 5 = 600
Since Average of A B C is 20 more than Average of D E
Take 600 - 20 * 3 = 540 (5 average units)
1 unit = 540 / 5 = 108
Hence 1 set of possible length:
D = 108cm, E = 108cm //
(A B C can be 108 + 20 = 128cm each)
B) total length of D+ E = 108 * 2 = 216cm
D : 1 unit + 16 cm
E : 1 unit - 20 cm
2 unit = 216 - 16 + 20 = 220cm
1 unit = 110cm
:. Length of D = 110 + 16 = 126cm //
(E = 90cm)
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