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Question
primary 6 | Maths
| Geometry
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Looking at the diagram, we have 3 overlapping squares.
We can see that :
∠a + ∠b + ∠c = 90° (left square)
∠d + ∠b + ∠c = 90° (middle square)
So comparing the two,
∠a = ∠d
Likewise,
∠b + ∠c + ∠d = 90° (middle square)
∠e + ∠c + ∠d = 90° (right square)
So comparing the two,
∠b = ∠e
Another way to think about it :
We can get to the middle square by rotating the left square rightwards.
Pushing it up by ∠a results in an extension by ∠d on its other side.
So the two angles are equal.
We can get to the middle square by rotating the right square leftwards.
Pushing it up by ∠e results in an extension by ∠b on its other side.
So the two angles are equal.
∠a + ∠b
= 90° - ∠c
= 90° - 15°
= 75°
∠c + ∠d + ∠e = 90°
(as seen from the diagram)
So,
∠a + ∠b + ∠c + ∠d + ∠e
= 75° + 90°
= 165°
Or
∠d + ∠e
= 90° - ∠c
= 90° - 15°
= 75°
∠a + ∠b + ∠c = 90°
(as seen from the diagram)
So,
∠a + ∠b + ∠c + ∠d + ∠e
= 90° + 75°
= 165°
∠a + ∠b + ∠c + ∠d + ∠e
= 1 angle of left square + 1 angle of right square - overlapping ∠c
(we cannot double count ∠c)
= 90° + 90° - 15°
= 180° - 15°
= 165°
Or
90° × 2 - 15°
= 180° - 15°
= 165°
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